\begin{frame}
  \frametitle{Derivatives of Trigonometric Functions}
  
  \begin{block}{}
    \begin{malign}
      \frac{d}{dx} \sin x &= \cos x &&
      \frac{d}{dx} \cos x = -\sin x
    \end{malign}
  \end{block}
  \medskip

  \begin{exampleblock}{}
    Differentiate the \emph{cosecant} $\csc x = \frac{1}{\sin x}$:
    \begin{talign}
      \frac{d}{dx} \csc x
      &= \frac{d}{dx} \left( \frac{1}{\sin x} \right) \\
      &\mpause[1]{= \frac{\sin x \cdot \frac{d}{dx} 1 - 1 \cdot \frac{d}{dx}\sin x}{(\sin x)^2} } \\
      &\mpause[2]{= \frac{-\cos x}{\sin^2 x} } \mpause[3]{= -\csc{x}\cdot \cot x} 
    \end{talign}
  \end{exampleblock}
  \vspace{10cm}
\end{frame}