\begin{frame} \frametitle{Derivatives of Trigonometric Functions} \begin{block}{} \begin{malign} \frac{d}{dx} \sin x &= \cos x && \frac{d}{dx} \cos x = -\sin x \end{malign} \end{block} \medskip \begin{exampleblock}{} Differentiate the \emph{secant} $\sec x = \frac{1}{\cos x}$: \begin{talign} \frac{d}{dx} \sec x &= \frac{d}{dx} \left( \frac{1}{\cos x} \right) \\ &\mpause[1]{= \frac{\cos x \cdot \frac{d}{dx} 1 - 1 \cdot \frac{d}{dx}\cos x}{(\cos x)^2} } \\ &\mpause[2]{= \frac{\sin x}{\cos^2 x} } \mpause[3]{= \sec{x}\cdot \tan x} \end{talign} \end{exampleblock} \vspace{10cm} \end{frame}