\begin{frame}
  \frametitle{Derivatives of Trigonometric Functions}
  
  \begin{block}{}
    \begin{malign}
      \frac{d}{dx} \sin x &= \cos x &&
      \frac{d}{dx} \cos x = -\sin x
    \end{malign}
  \end{block}
  \medskip

  \begin{exampleblock}{}
    Differentiate the \emph{secant} $\sec x = \frac{1}{\cos x}$:
    \begin{talign}
      \frac{d}{dx} \sec x
      &= \frac{d}{dx} \left( \frac{1}{\cos x} \right) \\
      &\mpause[1]{= \frac{\cos x \cdot \frac{d}{dx} 1 - 1 \cdot \frac{d}{dx}\cos x}{(\cos x)^2} } \\
      &\mpause[2]{= \frac{\sin x}{\cos^2 x} } \mpause[3]{= \sec{x}\cdot \tan x} 
    \end{talign}
  \end{exampleblock}
  \vspace{10cm}
\end{frame}