12/65
\begin{frame}
  \frametitle{1st Midterm Exam - Review}
  
  \begin{exampleblock}{}
    Find the precise value of
    \begin{talign}
      \log_5 198 - \log_5 10 - \log_5 99
    \end{talign}
    \pause
    We have
    \begin{talign}
      \log_5 198 - \log_5 10 - \log_5 99
      &\mpause[1]{= \log_5 \frac{198}{10} - \log_5 99} \\
      &\mpause[2]{= \log_5 \frac{198}{10\cdot 99}} \\
      &\mpause[3]{= \log_5 \frac{2}{10}} \\
      &\mpause[4]{= \log_5 \frac{1}{5}} \\
      &\mpause[5]{= -1}
    \end{talign}
  \end{exampleblock}
\end{frame}