\begin{frame} \frametitle{1st Midterm Exam - Review} \begin{exampleblock}{} Find the precise value of \begin{talign} \log_5 198 - \log_5 10 - \log_5 99 \end{talign} \pause We have \begin{talign} \log_5 198 - \log_5 10 - \log_5 99 &\mpause[1]{= \log_5 \frac{198}{10} - \log_5 99} \\ &\mpause[2]{= \log_5 \frac{198}{10\cdot 99}} \\ &\mpause[3]{= \log_5 \frac{2}{10}} \\ &\mpause[4]{= \log_5 \frac{1}{5}} \\ &\mpause[5]{= -1} \end{talign} \end{exampleblock} \end{frame}