\begin{frame} \frametitle{Area Between Curves} \begin{alertblock}{} What if we want the area between the curve and the $x$-axis? \end{alertblock}\smallskip \begin{center} \scalebox{.9}{ \begin{tikzpicture}[default] \def\mfun{(-.9 + (\x-3+\mfunshift)^2 - .1*(\x-3+\mfunshift)^4)} \diagram[1]{-.5}{6}{-1}{1.7}{1} \diagramannotatez \def\mfunshift{0} \begin{scope}[ultra thick] \draw[fill=cgreen,draw=none,opacity=.5] plot[smooth,domain=.5:2,samples=100] (\x,{\mfun}) -- (.5,0) -- cycle; \draw[fill=cgreen,draw=none,opacity=.5] plot[smooth,domain=2:4,samples=100] (\x,{\mfun}) -- cycle; \draw[fill=cgreen,draw=none,opacity=.5] plot[smooth,domain=4:5.5,samples=100] (\x,{\mfun}) -- (5.5,0) -- cycle; \draw[cred] plot[smooth,domain=.5:5.5,samples=100] (\x,{\mfun}); \node[anchor=north] at (.5,0) {$a$}; \node[anchor=north] at (5.5,0) {$b$}; \node[scale=1.8] at (.9,.5) {+}; \node at (.9,.9) {$A_1$}; \node[scale=1.8] at (5.15,.5) {+}; \node at (5.15,.9) {$A_3$}; \node[scale=1.8] at (3,-.6) {+}; \node at (3,-.25) {$A_2$}; \end{scope} \end{tikzpicture} } \end{center}\vspace{-.5ex} \begin{block}{} Let $f$ be continuous on $[a,b]$. \medskip Then the area between the curve $f$ and the $x$-axis from $a$ to $b$ is \begin{talign} A = \int_a^b |f(x)|dx \end{talign} \end{block} \pause \alert{To evaluate the integral, we split the it into $A_1$, $A_2$ and $A_3$.}\\ \pause Thus we must find the $x$-intercepts in $[a,b]$! \vspace{10cm} \end{frame}