\begin{frame}
  \frametitle{Fundamental Theorem of Calculus}
  
  \fundamental
  \medskip

  \begin{exampleblock}{}
    Find the area under $\cos x$ from $0$ to $b$ where $0\le b \le \pi/2$.
    \pause\medskip
    
    For $0 \le x \le \pi/2$, we have $\cos x \ge 0$. \pause Thus area = integral.
    \pause\medskip

    An antiderivative of $f(x) = \cos x$ is $F(x) = \pause \sin x$. 
    \pause
    Then
    \begin{talign}
      \int_0^b \cos x\;dx = \mpause[1]{\sin x \big]_0^b} \mpause{= \sin b - \sin 0} \mpause{= \sin b}
    \end{talign}
  \end{exampleblock}
  \vspace{10cm} 
\end{frame}