\begin{frame}
  \frametitle{Fundamental Theorem of Calculus}
  
  \fundamental
  \medskip

  \begin{exampleblock}{}
    Find the area under the parabola
    \begin{talign}
      f(x) = x^2
    \end{talign}
    from $0$ to $1$.
    \pause\medskip
    
    From $0$ to $1$ the curve is above the $x$-axis. \pause Thus area = integral.
    \pause\medskip

    An antiderivative of $f$ is $F(x) = \pause \frac{1}{3}x^3$. 
    \pause\medskip
    
    By the Fundamental Theorem, the area is:    
    \begin{talign}
      A = \int_0^1 x^2 \, dx= \mpause[1]{\frac{1}{3}x^3 \Big]_0^1} \mpause{= \frac{1}{3}1^3 - \frac{1}{3}0^3} \mpause{= \frac{1}{3}}
    \end{talign}
  \end{exampleblock}
  \vspace{10cm} 
\end{frame}