\begin{frame}
  \frametitle{L'Hospital's Rule}

  \begin{exampleblock}{}
    Evaluate the limit
    \begin{talign}
      \lim_{x\to 0^+} x^x
    \end{talign}
    \pause
    Then
    \quad $\lim_{x\to 0^+} x = 0$.
    \pause\medskip
    
    We write the limit as:
    \begin{talign}
      \lim_{x\to 0^+} x^x
      &\mpause[1]{ = \lim_{x\to 0^+} e^{\ln x^x} } \\
      &\mpause[2]{ = e^{\lim_{x\to 0^+} \left( x \ln x \right) } } \\
      &\mpause[3]{ = e^0 } \\
      &\mpause[4]{ = 1 }
    \end{talign}
  \end{exampleblock}

\end{frame}