\begin{frame}
  \frametitle{2nd Midterm Exam - Review}

  \begin{exampleblock}{}
    Find the derivative of
    \begin{align*}
      f(x) &= (\sqrt{x^5} - 3\sqrt[3]{x}) \cdot (6x^4 + 2x)\\
           &= \mpause[1]{(x^{\frac{5}{2}} - 3x^{\frac{1}{3}}) \cdot (6x^4 + 2x)}
    \end{align*}
    \pause\pause
    We have:
    \begin{align*}
      f'(x) 
      &= \mpause[1]{ (x^{\frac{5}{2}} - 3x^{\frac{1}{3}}) \cdot \frac{d}{dx} (6x^4 + 2x) + (6x^4 + 2x) \cdot \frac{d}{dx} (x^{\frac{5}{2}} - 3x^{\frac{1}{3}})} \\
      &\mpause[2]{=  (x^{\frac{5}{2}} - 3x^{\frac{1}{3}}) \cdot (24x^3 + 2) + (6x^4 + 2x) \cdot  (\frac{5}{2}x^{\frac{3}{2}} - x^{-\frac{2}{3}})} 
    \end{align*}
  \end{exampleblock}
\end{frame}