\begin{frame}
  \frametitle{2nd Midterm Exam - Review}

  \begin{exampleblock}{}
    Find the derivative of
    \begin{align*}
      f(x) = \frac{\sqrt{x^3}+4}{3x^2+7}
    \end{align*}
    using the quotient rule.
    \pause\medskip
    \begin{align*}
      f'(x) &= \mpause[1]{ \frac{(3x^2+7) \cdot \frac{d}{dx}(\sqrt{x^3}+4) - (\sqrt{x^3}+4) \cdot \frac{d}{dx} (3x^2+7)}{(3x^2+7)^2} } \\
      &\mpause[2]{= \frac{(3x^2+7) \cdot \frac{d}{dx}(x^{\frac{3}{2}}+4) - (\sqrt{x^3}+4) \cdot \frac{d}{dx} (3x^2+7)}{(3x^2+7)^2} } \\
      &\mpause[3]{= \frac{(3x^2+7) \cdot \frac{3}{2}\cdot x^{\frac{1}{2}} - (\sqrt{x^3}+4) \cdot 6x}{(3x^2+7)^2} } 
    \end{align*}
  \end{exampleblock}
\end{frame}