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\begin{frame}
  \frametitle{2nd Midterm Exam - Review}

  \begin{exampleblock}{}
    Find the derivative of
    \begin{align*}
      f(x) = \frac{\sqrt{x}-2}{\sqrt{x}+2}
    \end{align*}
    using the quotient rule.
    \pause\medskip
    \begin{align*}
      f'(x) 
      &= \mpause[1]{ \frac{(\sqrt{x}+2) \frac{d}{dx}(\sqrt{x}-2) - (\sqrt{x}-2) \frac{d}{dx}(\sqrt{x}+2) }{(\sqrt{x}+2)^2} } \\
      &\mpause[2]{=  \frac{(\sqrt{x}+2) \frac{1}{2\sqrt{x}} - (\sqrt{x}-2) \frac{1}{2\sqrt{x}} }{(\sqrt{x}+2)^2} } \\
      &\mpause[3]{=  \frac{(\sqrt{x}+2) - (\sqrt{x}-2) }{2\sqrt{x} (\sqrt{x}+2)^2} } \\
      &\mpause[4]{=  \frac{4}{2\sqrt{x} (\sqrt{x}+2)^2} } \mpause[5]{=  \frac{2}{\sqrt{x} (\sqrt{x}+2)^2} }
    \end{align*}
  \end{exampleblock}
\end{frame}