\begin{frame}
  \frametitle{Implicit Differentiation}

  \begin{exampleblock}{}
    Find $y'$ where $x^3 + y^3 = 6xy$.
    \begin{talign}
      y' = \frac{ 2y - x^2}{y^2 - 2x}
    \end{talign}
    
    Find the tangent to the curve at point $(3,3)$:\pause
    \begin{talign}
      y' = \frac{ 2\cdot 3 - 3^2}{3^2 - 2\cdot 3} = -1 
    \end{talign}
    \pause
    Thus the tangent is \quad $y - 3 = -1(x - 3)$.
  \end{exampleblock}
  \vspace{10cm}
\end{frame}