23/62
\begin{frame}
  \frametitle{Implicit Differentiation}

  Note that the derivative now depends on $x$ and $y$!
  \begin{talign}
    \frac{dy}{dx} = -\frac{x}{y} 
  \end{talign}
  
  \begin{center}
  \scalebox{1}{
  \begin{tikzpicture}[default,baseline=1cm,scale=.47]
    {\def\diaborderx{1cm}
    \diagram{-6}{6}{-6}{6}{1}}
    \diagramannotatez
    \begin{scope}[ultra thick]
      \draw[cgreen,ultra thick] (0,0) circle (5);
      \node[include=cred] at (3,4) {};
      \node[anchor=west] at (3.5,4) {slope $-\frac{3}{4}$};
      \node[include=cred] at (3,-4) {};
      \node[anchor=west] at (3.5,-4) {slope $\frac{3}{4}$};
    \end{scope}
  \end{tikzpicture}
  }
  \end{center}
\end{frame}