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\begin{frame}
  \frametitle{Differentiation Rules: Chain Rule}

  \begin{block}{}
    \begin{malign}
      (f\circ g)'(x) \;=\; f'(g(x)) \cdot g'(x)
    \end{malign}
  \end{block}  

  \begin{exampleblock}{}
    Differentiate
    \begin{talign}
      f(x) = (2x+1)^5 \cdot (x^3-x+1)^4
    \end{talign}
    \pause
    We have
    \begin{talign}
      f'(x) &= \mpause[1]{ (2x+1)^5 \cdot \frac{d}{dx} [(x^3-x+1)^4] }\\
            &\mpause[1]{ \hspace{1cm} + (x^3-x+1)^4 \cdot \frac{d}{dx} [(2x+1)^5] }\\
      &\mpause[2]{=  (2x+1)^5 \cdot 4(x^3-x+1)^3\cdot (3x^2-1) }\\
      &\mpause[2]{\hspace{1cm} + (x^3-x+1)^4 \cdot 5(2x+1)^4\cdot 2 }
    \end{talign}
  \end{exampleblock}

  \vspace{10cm}
\end{frame}