\begin{frame}
  \frametitle{Differentiation Rules: Chain Rule}

  \begin{block}{}
    \begin{malign}
      (f\circ g)'(x) \;=\; f'(g(x)) \cdot g'(x)
    \end{malign}
  \end{block}  

  \begin{exampleblock}{}
    Differentiate
    \begin{talign}
      f(x) = \left( \frac{x-2}{2x+1} \right)^9
    \end{talign}
    \pause
     We have
    \begin{talign}
      f'(x) &= \mpause[1]{9 \left( \frac{x-2}{2x+1} \right)^8 \frac{d}{dx} \frac{x-2}{2x+1} } \\
      &\mpause[2]{ = 9 \left( \frac{x-2}{2x+1} \right)^8 \frac{(2x+1) \cdot 1 - (x-2)\cdot 2}{(2x+1)^2} } \\
      &\mpause[3]{ = 9 \left( \frac{x-2}{2x+1} \right)^8 \frac{5}{(2x+1)^2} } \\
      &\mpause[4]{ = 45 \frac{(x-2)^8}{(2x+1)^{10}} } 
    \end{talign}
  \end{exampleblock}
  \vspace{10cm}

\end{frame}