\begin{frame}
  \frametitle{Derivatives of Exponential Functions}

  \begin{block}{}
    \begin{malign}
      \frac{d}{dx}(e^x) \;=\; e^x
    \end{malign}
  \end{block}
  \pause\medskip
  \begin{block}{}
    \begin{malign}
      \frac{d}{dx}(a^x) \;=\; \ln a \cdot a^x
    \end{malign}
  \end{block}
  \pause\medskip
  \begin{exampleblock}{}
    At what point on the curve $e^x$ is the tangent parallel to $y = 2x$?
    \pause\medskip
    
    Let $f(x) = e^x$
    \begin{talign}
      f'(a) = e^a = 2
    \end{talign}
    \pause
    Thus $a = \ln 2$, that is, the point is $(a,e^a) = (\ln 2, 2)$.
  \end{exampleblock}  
\end{frame}