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\begin{frame}
  \frametitle{1st Midterm Exam - Review}

  \begin{exampleblock}{}
    Find the inverse function of 
    \begin{talign}
      f(x) = \frac{1+\log x}{2\log x + 5}
    \end{talign}
    \pause
    We have
    \begin{talign}
      y = \frac{1+\log x}{2\log x + 5}
      &\mpause[1]{\implies y\cdot (2\log x + 5) = 1+\log x} \\
      &\mpause[2]{\implies 2y\log x + 5y = 1+ \log x} \\
      &\mpause[3]{\implies 2y\log x -\log x  = 1-5y } \\
      &\mpause[4]{\implies \log x \cdot (2y - 1)  = 1-5y } \\
      &\mpause[5]{\implies \log x = \frac{1-5y}{2y - 1} } \\
      &\mpause[6]{\implies x = 10^{\frac{1-5y}{2y - 1}} } 
    \end{talign}
    \pause[9]
    Thus the inverse function is $f(y) = 10^{\frac{1-5y}{2y - 1}}$.
  \end{exampleblock}

\end{frame}