\begin{frame}
  \frametitle{Logarithmic Functions: Base Conversion}
  
  If we want to compute $\log_a x$ but have only $\log_b$ then we can:
  \begin{block}{Base Conversion}
    \begin{talign}
      \log_a x = \frac{\log_b x}{\log_b a}
    \end{talign}
  \end{block}
  \pause\bigskip
  
  \begin{exampleblock}{}
    Compute $\log_4 16$ using $\log_2$. \pause
    \begin{talign}
      \log_4 16 \mpause[1]{ = \frac{\log_2 16}{\log_2 4}}
      \mpause[2]{ = \frac{4}{2}} \mpause[3]{ = 2}
    \end{talign}
  \end{exampleblock}
\end{frame}